"see explanation" " the function is a "color (blue)"parabola" "the following are required to graph it" • " coordinates f the vertex" • " x and y intercepts ...

Explanation: Please observe that the graph of #y = x^2+x+1# can never become negative.

See graph.. At the common points of the circle r = 3costheta and the cardioid r = 3 (1-costheta), r =3costheta=3 (1-costheta), giving costheta=1/2 In (-pi, pi), the angles alpha and beta as …

Hence, #f (x)# has the graph of the standard parabolic function #y=x^2# shifted by 2 units positive ("Up") on the #y-# axis.

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

The given expression: 0 = x^2+6x+9 is an equation, not a function. We can express the related function as: f (x) = x^2+6x+9 = (x+3)^2 In which case the given equation represents the zeros …

How do you graph the parabola #y=x^2-3x# using vertex, intercepts and additional points?

Dec 13, 2015 · How do you find the center, vertices, foci and eccentricity of x2 4 + y2 9 = 1?

See explanantion Given: y= (x^2-9x+20)/ (2x) First and foremost, the equation becomes undefined when the denominator is 0 Thus 2x!=0 => x!=0 larr "Asymptote" The true ...

Apr 10, 2016 · Vertical asymptotes occur as the denominator of a rational function tends to zero. To find the equation/s let the denominator equal zero. solve: x2 − 3 = 0 → x2 = 3 → x = ± √3 …